Comparing 2 color variables.

Question

Hi there, I'm trying to compare 2 colour variables but having no success.

Setting them like this:

 private var colour1 : Color = new Color(1.000, 0.945, 0.000, 1.000);
 // uvPoint refers to a conversion from a RaycastHit2D's point to uv coordinates
 private var colour2 : Color = theSprite.texture.GetPixel(uVPoint.x, uVPoint.y);

And comparing like this:

 // This happens on clicking on the colour.

 if (colour1 == colour2)
 {
    print("colour1 = colour2");
    print("colour1 = "+ colour1);
    print("colour2 = "+ colour2);
 }
 
 else if (colour1 != colour2)
 {
    print("colour1 != colour2");
    print("colour1 = "+ colour1);
    print("colour2 = "+ colour2);
 }

I keep getting the results:

colour1 != colour2

colour1 = RGBA(1.000, 0.949, 0.000, 1.000)

colour2 = RGBA(1.000, 0.949, 0.000, 1.000)

So if both colour variables have identical contents am I missing something fundamental about how colors should be compared?

The sprite texture is set to RGBA 32 bit, if that helps anything...

Thanks very much!

UPDATE:

Tried to print each individual colour value, which gives fuller results. Here's the culprit:

colour1.g = 0.9490196

colour2.g = 0.949

Am now wondering if using Color32 would solve this issue or if it would have the same issue? (Looking into it and will post an answer soon)

Answer 1

Best Answer

Answer by khenkel · Sep 08, 2014 at 10:30 AM

I would recommend to separately compare the r, g, b and a variables (respectively only the ones you need).

Also try printing the values of colour2 separately (eg. "print(colour2.r + ", " + colour2.g + ", " + colour2.b + ", " + colour2.a)") and check if they are REALLY equal to colour1. Unity logs often skip decimals.

You could also try out the following:

 if(colour1.Equals(colour2))
 {
     // Do stuff
 }

(but I don't know if this is actually the same as the == operator)

UPDATE:

As I said, Unity log often skips decimals. To compare those values up to 3 decimals you could do the following:

 if((int)(colour1.r * 1000) == (int)(colour2.r * 1000))
 {
     // Do stuff
 }

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Romano · Sep 08, 2014 at 10:31 AM 0

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Hey, the answers correct :) I tried giving the same answer and the site wouldn't let me which is why I grumpily closed the question. Thanks for answering.

Tactical_Beard Romano · Jan 16, 2016 at 10:29 PM 1

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The answer is inaccurate in most situations.

 Color Color1 = new Color(0, 0, 0.498f, 1);
 print((int)(Color1.b * 1000));//returns 497
 print($$anonymous$$athf.RoundToInt(Color1.b * 1000));//returns 498
         
 Color Color2 = new Color(0, 0, 0.333f, 1);
 print((int)(Color2.b * 1000));//returns 333
 print($$anonymous$$athf.RoundToInt(Color2.b * 1000));//returns 333

We can see why by printing Color1.b and Color2.b as doubles.

 double var1 = Color1.b;
 print(var1);//returns 0.497999995946884
 double var2 = Color2.b;
 print(var2); //returns 0.333000004291534

$$anonymous$$athf.RoundToInt returns the correct value every time where as (int) does not.

movAX13h · Feb 26, 2015 at 05:02 PM 0

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colour1.Equals(colour2) does not compare colors but object instance.

buronix movAX13h · Oct 26, 2016 at 06:23 PM 0

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Color.Equals(Color) compare the data, not the object instance, thats is made by referenceEquals.

Necronomicron · Dec 14, 2017 at 11:09 AM 0

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This is how you compare floats.

Comparing 2 color variables.

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