how to pass AJAX into php

Question

I have this kind of javascript, and inside this script I put an AJAX.

 sed = $("#progressbar").progressbar("option", "value");
     var getsed = sed +"ito to";
         $.ajax({
           type: 'POST',
           url: 'lesson_stat.php',
           data: {'variable': getsed},
         });

this is my lesson_stat.php

 <html>
     <head>
     </head>
     <body>
         <form action="lesson_stat.php" method="post">
             <?
             $myval = $_POST['variable'];
             echo "<script type='text/javascript'>"; 
             echo "alert('$myval')";
             echo "</script>";  
             ?>
         </form>
     </body>
 </html>

the problem was, i cannot retrieve the $myval that was being pass by AJAX..

Answer 1

Answer by Dave-Carlile · Jan 04, 2013 at 01:45 PM

This question would be better asked elsewhere since it's not strictly Unity related, but...

Looks like you're doing jQuery?

From the documentation, you need to specify a "success" event handler, which takes the results as one of the parameters.

http://api.jquery.com/jQuery.ajax/

 success(data, textStatus, jqXHR)

This would be part of the data passed to $.ajax().

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