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Question by Levantez · Jun 12, 2012 at 10:03 AM · guitextureresourceresources.loadall

GUI layout Label Dimension issue

I have 2+ GUI textures that have different dimension. I wanted them to display as full image, but image2 got clipped like this,

alt text alt text

Here's the code

 private Texture2D[] pages;
 private int currentPage;    
 private Rect guiScreenRect;
 
     protected void OnGUI()
     {
         if(isActivate)
         {
             float divider = 0.5f;
             
             // left top width height confine to 0-1 pages[currentPage].height*divider
             guiScreenRect = new Rect(0.0f,0.0f,1.0f*divider,0.9f*divider);
             
             guiScreenRect.x *= Screen.width;
             guiScreenRect.width *= Screen.width;
             guiScreenRect.y *= Screen.height;
             guiScreenRect.height *= Screen.height;
             
             GUILayout.BeginArea(guiScreenRect);
             GUILayout.Label(pages[currentPage]);
             GUILayout.EndArea();
         }
     }
 
 public void LoadResourcesBaseonID(string refID)
 {
     currentPage = 0;
     
     int ID = int.Parse(refID);
     string bookTitle = BookData.m_BookData[ID].GetTitle();    
         
     pages = Resources.LoadAll("BookPages/" + bookTitle, typeof(Texture2D)).Cast<Texture2D>().ToArray();
 }

Page01.jpg (107.8 kB)
Page02.jpg (100.9 kB)
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avatar image Mizuho · Jun 12, 2012 at 10:08 AM 1
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Couldn't this be done easily if you just used GUI.DrawTexture()? For example, for the left page, GUI.DrawTexture(new Rect(0, 0, Screen.width / 2, Screen.height), leftPageTexture);.

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Answer by sooncat · Jun 12, 2012 at 10:13 AM

Try this:(in OnGUI())

 GUILayout.BeginArea(guiScreenRect);
 GUI.Label(new Rect(0, 0, guiScreenRect.width, guiScreenRect.height), currentPage);
 GUILayout.EndArea();
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avatar image Levantez · Jun 12, 2012 at 10:16 AM 0
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This one work perfectly! Thank you.

avatar image Mizuho · Jun 12, 2012 at 10:20 AM 1
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@Zenneth: Should probably accept his answer if it worked for you.

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