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How do I get the 'normal' Sinus?
Hi there :), I'm sorry, I think my problem is a little one but it just doesn't work since 2 hours... The Sinus of 90 degree is 1.
Mathf.Sin(90) //doesn't work Mathf.Sin(90) multiplied Mathf.Rad2Deg //doesn't work Mathf.Sin(90) multiplied Mathf.Rad2Deg) //nope :) Mathf.Sin(90) multiplied Mathf.Deg2Rad) //Yeeeh.... oh no: only for 90 degrees
  
               so, since 2 hours I'm traying to get just the simple/normal sinus return (with stuff like Math.Pow(Mathf.Sin(),-1) and all kinds of combinations because I don't know what to do.....) Could somebody help me, please?  
Answer by whydoidoit · Jul 20, 2012 at 04:09 PM
     Mathf.Sin(90 * Mathf.Deg2Rad)
 
              yes, but like I wrote in my question it only works from 0° to 90°. $$anonymous$$athf.Sin(180 * $$anonymous$$athf.Deg2Rad) for example doesn't work.
Err - it's fine! What values were you expecting?
 0 = 0.000
 10 = 0.174
 20 = 0.342
 30 = 0.500
 40 = 0.643
 50 = 0.766
 60 = 0.866
 70 = 0.940
 80 = 0.985
 90 = 1.000
 100 = 0.985
 110 = 0.940
 120 = 0.866
 130 = 0.766
 140 = 0.643
 150 = 0.500
 160 = 0.342
 170 = 0.174
 180 = 0.000
 190 = -0.174
 200 = -0.342
 210 = -0.500
 220 = -0.643
 230 = -0.766
 240 = -0.866
 250 = -0.940
 260 = -0.985
 270 = -1.000
 280 = -0.985
 290 = -0.940
 300 = -0.866
 310 = -0.766
 320 = -0.643
 330 = -0.500
 340 = -0.342
 350 = -0.174
 
                 ok, that's a cool answer :D so, right know I saw that there is an E-08 at the end... I just have to round it.... I'm, sorry _
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