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Question by mevsvader · Dec 14, 2021 at 05:21 PM · string

Please Help. Tryna make a script that binds controls to random keys. but i cannot find a way to do it quickly and can only set up each key manualy

my plan was to have a char array of all 26 letters of the alphabet and then randomly pick 1 of them to set as a new bind for a control, but i cannot find a way to turn a string into code, to then execute a BindForLeft = keycode.Letter (it would just be a capital letter of the alphabet).

is there any way to turn string into code? i dont want to have to write an if statement for every letter, plus i might also add other language letters so it would be very time consuming.

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Best Answer

Answer by Hellium · Dec 14, 2021 at 06:27 PM

The letter keycodes from A to Z are following

CODE NOT TESTED

 int count = (int)(1 + 'z' - 'a');
 List<UnityEngine.KeyCode> keycodes = new List<KeyCode>(count);
 for (int i = 0; i < count; ++i)
     keycodes.Add(KeyCode.A + i);
 
 int bindingIndex;
 bindingIndex = Random.Range(0, keycodes.Count);
 BindForLeft = keycodes[bindingIndex];
 keycodes.RemoveAt(bindingIndex);

 bindingIndex = Random.Range(0, keycodes.Count);
 BindForRight = keycodes[bindingIndex];
 keycodes.RemoveAt(bindingIndex);

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