Is this reading the full range of Perlin Noise?

Hi all =]

I have written a script to take samples across the Mathf.PerlinNoise spectrum, and am surprised at the result. So I have come to ask, is this a full sweep of the Perlin Noise 'map', or am I just getting a high-res sample of a small area? I have done more subdivisions (higher resolution of samples between 0-1), but it just follows the pattern in the pictured curve. I am passing values between zero and one to values in static function PerlinNoise (x : float, y : float) : float (I hope!). Is this the full output? My (limited) understanding was the greater the number of samples (the more times you sub-divided between 0-1), the more uneven the output would become (i.e. heaps of jaggies). This is the first time I have used perlin, so if I'm waaay off, please tell me =]

 var step : Vector2 = Vector2( starFieldSize.x / starCount.x, starFieldSize.y / starCount.y );
 var index : int = 0;
 for (var v:int = 0; v < starCount.y; v ++)
 {
     for (var i:int = 0; i < starCount.x; i ++)
     {
         // get perlin var for X-Y (i-v) coords
         var perlinCalc : Vector3 = new Vector3( (i * step.x), (v * step.y), 0 );
         
         perlinCalc.z = Mathf.PerlinNoise( perlinCalc.x / starFieldSize.x, perlinCalc.y / starFieldSize.y );
         
         Debug.Log ( "perlinCalc + " + perlinCalc + " : perlin = " + perlinCalc.z );
         
         starPos[index ++] = new Vector3( perlinCalc.x - randomizePos.x + (2.0 * perlinCalc.z * randomizePos.x), perlinCalc.y - randomizePos.y + (2.0 * perlinCalc.z * randomizePos.y), 0.0 + (randomizePos.z * perlinCalc.z) );
     }
 }