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Question by ShaggySlade · Dec 11, 2016 at 12:14 PM · enumdivide

Dividing values of enums

I'm not sure if I am asking this the right way but here it goes.

I have been following a tutorial series on youtube by bergzergarcade and I came across an issue I just cant cant figure out. The tutorial that covers what I'm referring to is here (https://www.youtube.com/watch?v=KG26blhtYnA&list=PLE5C2870574BF4B06∈dex=19)

Anyway my question refers to the below code:

 GetSkill((int)SkillName.someskill).AddModifier(new ModifyingAttribute(GetPrimaryAttribute((int)AttributeName.AttributeName1), .33f));
 
     GetSkill((int)SkillName.someskill).AddModifier(new ModifyingAttribute(GetPrimaryAttribute((int)AttributeName.AttributeName2), .33f));
 
     GetSkill((int)SkillName.someskill).AddModifier(new ModifyingAttribute(GetPrimaryAttribute((int)AttributeName.AttributeName3), .33f));
     

The code "works" but it does not calculate "someskill" correctly.

If AttributeName1, AttributeName2, and AttributeName3 are each 100, "someskill" = 99 but I want it to 100 as well. I was wondering how I go about coding it so it calculates the 3 AttributeNames THEN divide by 3( or * .33)

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avatar image hexagonius · Dec 11, 2016 at 03:03 PM 0
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I think nobody can answer this, because everything that's happening is in the methods you call which are not shown.I have no idea what's going on behind the curtains

avatar image ShaggySlade hexagonius · Dec 11, 2016 at 08:27 PM 0
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Well like i said the code is "working" but ill try to give more information. I guess what Im wonder is, what is the best way to go about getting the remainder of each "AtttibuteName" to be included when calculating. Or in other words how can I combine those to give my code a single value to divide?

the mentioned video shows more code. Around the 7 $$anonymous$$ute mark (I think) and it will probably better explain whats going on than I can.

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