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Question by spacelyjoe · Aug 24, 2013 at 05:20 PM · pausedisableteleportwait

How would you make something disapear for a second?

I want my code so my object disappears and when it reappears it's in a different position. i tried to make it so the object is off the screen while the the count is under 2 seconds and then it reappears in one of the teleport spots. Is there a better way to do this?

     if (count < 2){
         transform.position = new Vector3(600000, 1000, transform.position.z);
         count += Time.deltaTime;
     }
                 
     if (count >= 2){
         transform.position = new Vector3 (teleportSpot.transform.position);
     }
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Answer by doctorseus · Aug 24, 2013 at 05:28 PM

You could disable the rendering of the object. Look here for more information. http://answers.unity3d.com/questions/14165/show-and-hide-a-prefab-or-gameobject.html

or use the SetActive method http://docs.unity3d.com/Documentation/ScriptReference/GameObject.SetActive.html

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avatar image aldonaletto · Aug 24, 2013 at 05:58 PM 0
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SetActive is better because the object literally disappears from scene. If only its renderer is disabled, weird collateral effects may result: other objects may collide with it, or - even worse - its children may still be visible (if they have their own renderers).

If using SetActive, remember that most functions in the inactive object stop executing: it must be activated by an external object, or with Invoke. The example code below makes the object disappear when clicked, and reappear 5 seconds after in the same position:

 function On$$anonymous$$ouseDown(){
     Invoke("Reappear", 5); // will reappear in 5 seconds
     gameObject.SetActive(false); // disappears
 }
 
 function Reappear(){
     gameObject.SetActive(true); // I'm back!
 }



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