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Question by saher2001002 · Mar 21, 2018 at 05:22 PM · looprandom.range

trying to use while that have 2 random range inside to get a any possible numbers that it will create a num

     float num1=0, num2=0;
       for(int i=0; i<=1; i++)
       {             
          num1 = Random.Range(0, 9.6f);
          num2 = Random.Range(0, 9.6f);
          while (num1 + num2 != 9.6)
          {
               num1 = Random.Range(0f, 9.6f);
                num2 = Random.Range(0f, 9.6f);
          }

sorry if this is a noob question i just started making games(2D)

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avatar image saher2001002 · Mar 21, 2018 at 08:31 PM 0
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the error is that every time i run the script unity crash(kinda it just dont anything and dont respond windows not saying its not responding )

avatar image hexagonius · Mar 21, 2018 at 09:12 PM 3
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you're stuck in an infinite loop because the chance the sum of your random numbers is 9.6 is rather not existent.

avatar image Scribe · Mar 21, 2018 at 09:21 PM 3
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As @hexagonius says you are in a (close to) infinite loop, there are thousands of possible floating point numbers between 0 and 9.6.

How about just randomise one and calculate the second. It will be the same random distribution (if my maths serves).

 num1 = Random.Range(0.0f, 9.6f);
 num2 = 9.6f - num1;
avatar image Bunny83 Scribe · Mar 22, 2018 at 03:04 AM 2
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Actually there are pretty much a billion possible floating point numbers between 0 and 1 (specifically 2^30 == 1073741824). Your solution is of course correct and the right way to approach this.

avatar image Rugbug_Redfern · Mar 22, 2018 at 01:33 AM 1
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What are you asking? Can you elaborate?

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Answer by losingisfun · Mar 22, 2018 at 04:26 AM

I highly recommend changing this.

From your code, I'm guessing you want two numbers, and for both of them to equal 9.6f? If that's the case, you should try doing something a little less verbose like:

 float num1 = Random.Range (0f, 9.6f);
 float num2 = 9.6f - num1;

which will achieve the exact same thing, but with possibly a thousand less operations.

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