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Imported cube vertex count different than expected
I made a cube in maya, with width, height ad depth divisions set 16. I was expecting a cube with a total of 16^3, 4096 vertices, but on importing and attempting to normalize the cube, I got a return of 1734 vertices. How do I calculate the vertices of not cubing the divisions?
Answer by HappyMoo · Jan 01, 2014 at 05:11 AM
It depends on if your sub-quads reuse verts or copies them. Are the numbers different from what maya showed or just different from what you calculated?
With reusing verts on every face, but not on the edges, I expect 6 * 17*17 = 1734 verts
Different than calculated, where did you get the 17s from
if you have 2 divisions, you have 3 * 3 verts:
x x x
x x x
x x x
so if you have 16 divisions, you have 17*17 verts.... per face
You seem to think that the subdivisions are some kind of structure that is also inside the cube. It's just on the surface of the cube. There is no vertex inside the cube.