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Question by Lemo76 · Apr 15, 2015 at 03:50 AM · javascriptlistvaluesimpleindex

Set Specific List Value

This is a very simple question, but I'm stuck on it and I can't find the right answer.
Here goes,

 private var Filenames : List.<String>;
 
 function Start () {
 Filenames[4] = "test";
 print (Filenames[4]);
 }

It always prints out as "Null Reference Exception, hinting to the Filenames[4] = "test"; line.

How do I get it to work?
Thanks!

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avatar image Mehul-Rughani · Apr 15, 2015 at 04:39 AM 0
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make Filename public and then define the size of list in inspector for ex. 5 and then run it ... hope it will help u

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Answer by CowNecromancer · Apr 15, 2015 at 09:08 AM

try use... Debug.Log (Filenames[4]); NOT print

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Answer by Olgo · Apr 15, 2015 at 04:26 AM

I'm not used to javascript, but I would have to say you need declare the list before referencing objects in it.

var Filenames = ["zero", "one", "two", "three", "test"];

Above you're looking for the fourth index of the list, when there's nothing in the list yet.

If it were c# you would need List Filenames = new List(); This populates the list, while just saying List Filenames; gets you nothing but null reference exceptions.

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Answer by Tomer-Barkan · Apr 15, 2015 at 04:37 AM

List probably needs adding elements in order to work properly. consider using an array:

 var x = [];
 x[4] = "aaa";
 print(x[4]);
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avatar image Lemo76 · Apr 15, 2015 at 04:57 AM 0
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Thanks, figured it out.

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