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Question by MiroslavMilanov · Oct 22, 2017 at 09:13 AM · transformdown

transform.down not working.

I'm trying to run the following code:

         if (Input.GetKeyDown (KeyCode.S) && groundScript.isGrounded == false) {
             rig.AddForce (transform.down * jumpHeight);
         }

But after saving, I'm receiving the following error: Assets/Scripts/Jump.cs(23,28): error CS1061: Type UnityEngine.Transform' does not contain a definition for down' and no extension method down' of type UnityEngine.Transform' could be found. Are you missing an assembly reference?

The thing is just above that line of code I have:

         if (Input.GetKeyDown (KeyCode.Space) && groundScript.isGrounded == true) {
             rig.AddForce (transform.up * jumpHeight);
         }

And it is working perfectly fine. .down is highlighted in red and doesn't show as a possible Vector3. Any ideas why?

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Answer by Dragate · Oct 23, 2017 at 01:14 PM

https://docs.unity3d.com/ScriptReference/Transform.html

There is no transform.down. But you can easily calculate it since it's the opposite of transform.up.

 rig.AddForce (-transform.up* jumpHeight);
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Answer by FabDynamic · Oct 23, 2017 at 09:25 PM

One way to do it:

Vector3 transformDown = transform.up * -1.0f;

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avatar image Bunny83 · Oct 24, 2017 at 03:13 AM 0
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Why multiplying the vector by "-1.0f" when an unary $$anonymous$$us is shorter and faster?

avatar image FabDynamic Bunny83 · Oct 26, 2017 at 12:15 AM 0
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Only in order to be utterly and transparently clear to the reader what is going on. You are right that it doesn't matter.

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Answer by theLittleSettler · Oct 23, 2017 at 01:12 PM

Well, its a bit silly, but there really isn't a down (or left, or backwards) defined. I guess its just Transform doesn't have them (though Vector3 does). Odd they would define them in one and not the other.

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