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Question by JoshMBeyer · Mar 22, 2014 at 06:27 PM · gameobjectarraycheckinis

How to check if a specific gameobject is in the array?

I am working on a different inventory type system. What I would like it do here is be able to search the array, and if there is in fact a "Sphere" in the array, tell the user they have 1 or more Spheres. Not sure if it is possible, or maybe I should be using a list. Not sure. Any advice or tips??

here is the inventory script. I have other scripts to add items to the array already.

 using UnityEngine;
 using System.Collections;
 
 public class Inventory : MonoBehaviour {
 
     public GameObject[] items;
 
 
     // Use this for initialization
     void Start () 
     {
         
     }
     
     // Update is called once per frame
     void Update () 
     {
     
     }
 
     void OnGUI()
     {
         //Insted of indexing of a specific, I want to check if any gameobject in items 
         //is equal to FindWithTag "Sphere". Is that possible?
         if (items[0] == GameObject.FindWithTag("Sphere"))
         {
             GUI.Label(new Rect(100, 100, 100, 100), "You have a (or this many) sphere(s)");
         }
 
     }
 
 
 }
 
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Answer by SkaredCreations · Mar 22, 2014 at 06:36 PM

If the array list is dynamic and you can add/delete entries, then just don't use an array but a generic List (add "using System.Collections.Generic" at top of your script) and use Contains():

 using UnityEngine;
 using System.Collections;
 using System.Collections.Generic;
 
 public class Test : MonoBehaviour {
 
     public List<GameObject> items;
 
     void OnGUI()
     {
     GameObject sphere = GameObject.FindWithTag("Sphere");
     if (sphere != null && items.Contains(sphere))
         {
             GUI.Label(new Rect(100, 100, 100, 100), "You have a (or this many) sphere(s)");
         }
     }
 
 }

To add a GameObject to the list: items.Add(yourGO); To remove from the list: items.Remove(yourGO);

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avatar image JoshMBeyer · Mar 22, 2014 at 06:39 PM 0
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Thank you that answered my question perfectly.

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