spawn game object in random position

Question

//hello i am building an AR app and trying to spawn game object in random position but i can't find the solution any help ? thank you ,hello , i am building an AR app and trying to spawn a game object in a random position but i can't find the solution any ideas ? // //code// using System.Collections; using System.Collections.Generic; using UnityEngine;

public class spawnscript : MonoBehaviour { public Transform[] spawnPoints; public GameObject [] balloons;

 // Start is called before the first frame update
 void Start()
 {
     StartCoroutine(Startspawning());
 }

 IEnumerator Startspawning(){
     yield return new WaitForSeconds(4);

     for (int i = 0 ; i < 3 ; i++){
         Instantiate(balloons[i], spawnPoints[i].position, Quaternion.identity);
     }
     StartCoroutine(Startspawning());
 }

} ,

Answer 1

Best Answer

Answer by privatecontractor · Jan 20 at 06:55 PM

Hi @jassemdegani,

So your spawn position is Vector3 if dealing with 3D or Vector2 if 2D. Each of them consist of float values. So for 3D:

 [Serializefield] Vector3 m_maxPosition;
 [Serializefield] Vector3 m_minPosition;
 
 public void GetNewSpawPosition()
 {
  return new Vector3(Random.Range(m_minPosition.x, m_maxPosition.x), Random.Range(m_minPosition.y, m_maxPosition.y, Random.Range(m_minPosition.z, m_maxPosition.z));
 }

So in inspector you will need to assign min and max values. Hope will work for you. Sry for mistakes in speling (editing on phone )

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