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Question by gegebel · Aug 24, 2014 at 01:46 AM · uiinstantiatebutton

instantiate a button in a panel in new uGUI

I have a List in a script which is being increased every now and then. I would like to instantiate a button in a panel with a grid layout for every string in the list. Something like:

 foreach(int i=0; i < list.Count; i++){
     instantiate(button);
     button.text.text = list[i]; 
 }

I'm not sure how to say it's got to be in the panel though.

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Answer by Kirbyrawr · Aug 24, 2014 at 02:38 AM

I think you want to put them inside the layout right?

If it's right, here's the code:

  public GameObject yourGridLayout;
     
     //Here i put on click but you need to put your method.
     void OnClick(){
     
     for(int i = 0; i < list.Count; i++){
     
      var buttonInstantiate = Instantiate(button);
      buttonInstantiate.text = list[i];
      buttonInstantiate.transform.gameObject.parent =   yourGridLayout.transform;
     
     }
     
     }

Hope it helps, remember that i missed the class on the script.

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avatar image gegebel · Aug 24, 2014 at 02:19 PM 0
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parent did the trick, thanks

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