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I cannot figure out what my error is...
Hi, I am a beginner at programming in C#, and I need help with finding the issue that I am having right now. Here is the code below:
using UnityEngine;
using System.Collections;
public class NetworkManager : MonoBehaviour {
private const string typeName = "UniqueGameName";
private const string gameName = "RoomName";
private void StartServer()
{
Network.InitializeServer(4, 25000, !Network.HavePublicAddress());
MasterServer.RegisterHost(typeName, gameName);
}
void OnServerInitialized()
{
Debug.Log("Server Initializied");
}
void OnGUI()
{
if (!Network.isClient && !Network.isServer)
{
if (GUI.Button(new Rect(100, 100, 250, 100), "Start Server"))
StartServer();
}
}
private HostData[] hostList;
private void RefreshHostList()
{
MasterServer.RequestHostList(typeName);
}
void OnMasterServerEvent(MasterServerEvent msEvent)
{
if (msEvent == MasterServerEvent.HostListReceived)
hostList = MasterServer.PollHostList();
}
private void JoinServer(HostData hostData)
{
Network.Connect(hostData);
}
void OnConnectedToServer()
{
Debug.Log("Server Joined");
}
void OnGUI()
{
if (!Network.isClient && !Network.isServer)
{
if (GUI.Button(new Rect(100, 100, 250, 100), "Start Server"))
StartServer();
if (GUI.Button(new Rect(100, 250, 250, 100), "Refresh Hosts"))
RefreshHostList();
if (hostList != null)
{
for (int i = 0; i < hostList.Length; i++)
{
if (GUI.Button(new Rect(400, 100 + (110 * i), 300, 100), hostList[i].gameName))
JoinServer(hostList[i]);
}
}
}
}
// Use this for initialization
void Start () {
}
// Update is called once per frame
void Update () {
}
}
And my error says:
Assets/NetworkManager.cs(52,14): error CS0111: A member 'NetworkManager.OnGUI()' is already defined. Rename this member or use different parameter types
PLEASE HELP!
Thanks! -Eric N.
Answer by richyrich · Jan 19, 2015 at 03:45 AM
You need to remove this code:
void OnGUI()
{
if (!Network.isClient && !Network.isServer)
{
if (GUI.Button(new Rect(100, 100, 250, 100), "Start Server"))
StartServer();
}
}
It is a subsection of the other function by the same name.
The error message is telling you that you cannot have two methods by the same name
Note: Technically you can have two functions with the same name, but they must have different parameters.
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