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Question by Delfuego · Jan 15, 2015 at 05:41 AM · jsondeserialize

Deserializing JSON

Hello! I have json with list of friends and information about that from vk.com api:

   response: {
     count: 262,
     items: [{
     id: 38097687,
     first_name: 'Aida',
     last_name: 'Fazy',
     online: 1
     }, {
     id: 4261331,
     first_name: 'Aisa',
     last_name: 'Red',
     online: 0
     }, {
     id: 35630046,
     first_name: 'Alex',
     last_name: 'Feer',
     online: 1
     }]
     }


How can I Debug.log each friend first_name + last_name using any JSON lib for parsing? I tried several hours to do that and still no progress becaurse lack of knowledge :(

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Answer by Cocobongo · Jan 15, 2015 at 09:03 AM

My preference when working with JSON is Boomlagon's plugin (that's in C#). It's free and does the work.

Boomlagon JSON

You would then do something like:

 string json = "...";
 var parsedJson = JSONObject.Parse(json);
 var items = parsedJson["response"].Obj["items"].Array;
 for(var i = 0 ; i < items.Length ; ++i) {
     Debug.Log(items[i].Obj["first_name"].Str);
 }

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