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Question by harrietradcliffe · Sep 09, 2013 at 04:37 PM · positionvector

Random Range Position

Hello... our screen size is Android wide 3:6. We have this object that when clicked it must be changing position. This object is a plane.

here is our code for changing position

 var position =Vector2(Random.Range(0,1),Random.Range(1,0));

we are not sure if we must use Vector2 and what random.range we should declare help please. thank you

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avatar image perchik · Sep 09, 2013 at 04:39 PM 0
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What are you trying to achieve?

avatar image harrietradcliffe · Sep 09, 2013 at 04:44 PM 0
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the plane should change its position randomly when clicked. it should continue that way while the timer is running.

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Answer by mirkobon · Sep 09, 2013 at 05:20 PM

 var randomy : int;
  var randomx : int;
 
 function Update ()
 {
 // do here on mouse click
 
 randomy = Random.range(-1.5,1.5)
 randomx = Random.range(-3,3)
 
 transform.position.y = randomy
 transform.position.x = randomx
 
 }

tell me if this worked

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Answer by Seizure · Sep 09, 2013 at 04:47 PM

Watch using Random.range with int's, the max is EXCLUSIVE see reference Random.Range

So you are going from a range of 0 to 0 on the x and y is messed up anyways with a range min of 1 and max of 0 thats at least backwards.

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avatar image mirkobon · Sep 14, 2013 at 07:18 AM 0
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sorry i were actualy wanting to make a float but i forgot to edit

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