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Question by talyon · Jul 16, 2014 at 04:37 PM · c#randomspawnvector3.lerp

move gameobject into a random position and the spawn an enemy

hello, this is the script that I did.

 void Start () 
 {
     posFinale = new Vector3(Random.Range (-17.0f,18.0f),Random.Range (-10.0f,11.0f),0);
 }
 
 void Update () 
 {
     transform.Translate ((posFinale - transform.position)* speed * Time.deltaTime);

     if ((transform.position == posFinale) && !(fatto))
     {
         fatto = true;
         Instantiate(add,transform.position, Quaternion.identity);
         Destroy (gameObject);
     }
     Debug.Log (posFinale);
 }

But I have a problem, when it comes to the location is not that precise so do not spawn the enemy.

I also tried with vector3.lerp but does the exact same thing

Is there another way to do this?

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avatar image iwaldrop · Jul 16, 2014 at 05:27 PM 1
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I'd take a look at Vector3.$$anonymous$$oveTowards.

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Answer by robertbu · Jul 16, 2014 at 05:42 PM

As @iwaldrop suggests, Vector3.MoveTowards() will work. Lerp() will work if you in a linear fashion (i.e. the final parameter be an increasing fraction between 0 and 1. You can also make your existing code work. The problem is this check:

  if ((transform.position == posFinale) && !(fatto))

The chance of transform.position being exactly equal to posFinal is small. So you can instead do the check this way:

 if (Vector3.Distance(transform.position, posFinale) < threshold && !(fatto))

'threshold' is either a variable you define or some constant. It is a small value that defines close enough.

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avatar image talyon · Jul 17, 2014 at 04:30 PM 0
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I thought I had a similar method but did not know how to do it, thanks a lot!

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