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Question by
chakuze · Apr 26, 2014 at 11:41 AM ·
javascriptfunction
Function is called twice and I've no idea why
The function attack() is called twice even though it shouldn't be possible, because the counter variable, which I've implented for debug purpose is higher than 0. see this pic for detailed info: http://imgur.com/dECW4yN
thanks in advance for a reply!
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Answer by Desination-X · Apr 26, 2014 at 11:55 AM
Try putting counter++; before AttackDamage(); This should help.
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