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Question by largow · Apr 17, 2014 at 12:29 AM · 2dspawnrespawn

GameObject is spawned twice

Hello guys, i'm having some trouble spawning my player on my 2D game. The isse is that when i try to spawn my player on a spawn point, my player is spawned twice. That means that my Spawn function is called twice, I can't figure out why is that happening.

Here's the code:

 using UnityEngine;
 using System.Collections;
 
 public class Respawn : MonoBehaviour {
 
     public GameObject character;
     public Transform ptoDeSpawn;
 
     // Use this for initialization
     void Start () {
 
         SaveCheckPoint (ptoDeSpawn.position.x,ptoDeSpawn.position.y,ptoDeSpawn.position.z);
 
         Vector3 pos = new Vector3 (PlayerPrefs.GetFloat("checkPointX"),PlayerPrefs.GetFloat("checkPointY"),PlayerPrefs.GetFloat("checkPointZ"));
 
         Spawn(character,pos);
 
     }
     
     // Update is called once per frame
     void Update () {
     
     }
 
 
     void SaveCheckPoint(float posX, float posY, float posZ){
 
         PlayerPrefs.SetFloat ("checkPointX", posX);
         PlayerPrefs.SetFloat ("checkPointY", posY);
         PlayerPrefs.SetFloat ("checkPointZ", posZ);
     }
 
     void Spawn(GameObject character, Vector3 pto){
         if (character) {
             GameObject p = Instantiate (character, pto, Quaternion.identity) as GameObject; 
             CamaraController cam = Camera.main.gameObject.GetComponent<CamaraController> ();
             cam.target = p.transform;
         } else {
             print("is null");
         }
 
 
     }
 }


Thanks!

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avatar image Benproductions1 · Apr 17, 2014 at 08:08 AM 0
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Do you have the script attached twice by any chance? Are you calling Spawn from anywhere else?

avatar image Jenesis · Apr 17, 2014 at 10:33 AM 0
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Try adding a Debug.Log call to the Spawn method, it should help you work out where it's being called from. Something like Debug.Log("Spawning");

This will print the word "Spawning" to the Unity console. If you select it, you'll be able to see the stack trace for the debug output. That lets you work out where it's being called from, so you can see if it's being called anywhere other than the Start method. If it's not, you must have two instances of the script somewhere.

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