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Question by Sovraya · Feb 25, 2013 at 11:16 AM · onguigui.box

How to hide GUI.box if condition is false?

Hi,

I'm using GUI.box to show a healthbar for the mobs, but I only want to show the GUI.box if there is a target.

This is my code at the moment.

     public GameObject target;
     public bool existsTarget;
 
     // Use this for initialization
     void Start()
     {
         
         PlayerAttack pa = (PlayerAttack)GetComponent("PlayerAttack");
         target = pa.target;
         
         existsTarget = false;
     }
 
     // Update is called once per frame
     void Update()
     {
         
         if(target != null)
         existsTarget = true;
     else 
         existsTarget = false;
         
         
     }
 
     void OnGUI()
     {
         if(existsTarget)
               GUI.Box(new Rect(500, 10, healthBarLength, 20), curHealth + "/" + maxHealth);
     }


Unfortunately this doesn't show any healthbars at all. Any ideas as to why?

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Answer by Gabriel Quijada · Feb 25, 2013 at 01:01 PM

I hide the GUI elements in the screen, but not in visible screen, like this

 void OnGUI()
 {
 if(existsTarget)
 {
 GUI.Box(new Rect(500, 10, healthBarLength, 20), curHealth + "/" + maxHealth);
 }
 else
 {
 GUI.Box(new Rect(Screen.width, 10, healthBarLength, 20), curHealth + "/" + maxHealth);
 }
 }

this is helpfull because you use the screen parameters like uhm...global? you don't have to know the resolution of screen, Unity calculate this. Good Luck.

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avatar image Sovraya · Feb 25, 2013 at 01:08 PM 0
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Thanks for the reply, however it didn't work unfortunately. The problem is that the GUI.Box doesn't show at all, so at the moment it is already "hidden". Although I did add the else anway, probably solved a problem later on :P

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