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Question by JULike · Nov 11, 2011 at 01:03 PM · javascriptfunctionsparameters

calling a function from another script

Hi,

I have two scripts attached to one prefab I'm trying to call a function in one of them from the other:

In the caller

    var rightLines = CheckRight.checkRight(X, Y);

in the other script named CheckRight.js:

    function checkRight(X, Y){
     ...
     return rightLines}
 

Any help much appreciated :)

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Answer by syclamoth · Nov 11, 2011 at 01:05 PM

If you have a reference to the gameObject on which your 'CheckRight' script is a component, just use

 checkRightGameObject.GetComponent(CheckRight).checkRight(X, Y);
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avatar image syclamoth · Nov 11, 2011 at 02:38 PM 0
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If they're both on the same object, you just need to use

 GetComponent(CheckRight).checkRight(X, Y);
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Answer by JULike · Nov 11, 2011 at 02:42 PM

Thanks,

Both scripts are attached to the same object called 'tile', do I need to explicitly reference 'tile' from one script to access its functions from the other script, if so how?

Kind Regards

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avatar image syclamoth · Nov 11, 2011 at 02:43 PM 0
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AAAND you doubleposted. This is why it's easier to just use comments- they don't have to go through the moderation queue!

avatar image JULike · Nov 11, 2011 at 02:49 PM 0
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Thanks,

Script1 GetComponent(CheckRight).checkRight(adjustedX, adjustedY);

Script2 (CheckRight.js) function checkRight(adjustedX, adjustedY){}

Ok, so both are attached to the same game object I just checked in the inspector. And I'm getting $$anonymous$$ethod not found exception, when I double click on it it takes me to the attempted call in Script1

Soz about double posting :/

Thanks

avatar image syclamoth · Nov 11, 2011 at 03:22 PM 0
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Hmm, I'm not so familiar with JS- it's possible that you need to use

 var checkRight : CheckRight = GetComponent(CheckRight);
 answer = checkRight.checkRight(X, Y);
avatar image JULike · Nov 11, 2011 at 03:28 PM 0
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Thanks,

Same $$anonymous$$issing$$anonymous$$ethodException $$anonymous$$ethod not found: 'CheckRight.checkRight'.

avatar image syclamoth · Nov 11, 2011 at 03:31 PM 0
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Did you make the function a public function? I always get confused by the fuzzy syntax in JS, but that might be the problem (unless it's one of those things that magically work anyway).

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