koobas.hobune.stream
Is this spec method any faster than using pow()?
The line below uses a different approach to specular falloff. Essentially it would take the spec falloff gradient[c] and apply "black crushing" (a la photoshop levels) to simulate glossiness[g]. Then, it multiplies the end result to simulate spec power[s].
(1-((1-c)/(1-g)))*s
c=input color, g=glossiness, s=spec strength
The problem is, I don't know if this is any faster than pow()! Does anyone have some better insight into the math behind this?
Thanks!
-Dan
Well you don't take it to the power of s, you multiply it by s.
So is it faster: yes, probably
is it the same as pow: no, certainly not ;)
pow takes the first argument to the power of the second
