koobas.hobune.stream
BeginVertical won't compile when no style is provided
Hi,
i'm trying to create a very simple GUI with Unity, here is my javascript code:
function OnGUI() {
GUILayout.BeginVertical(GUIContent("test"));
GUILayout.EndVertical();
}
when the script is 'compiled' it gives me the following error:
Assets/NewBehaviourScript.js(2,40): BCE0023: No appropriate version of 'UnityEngine.GUILayout.BeginVertical' for the argument list '(UnityEngine.GUIContent)' was found.
when i add a style to the BeginVertical constructor, like this:
function OnGUI() {
GUILayout.BeginVertical(GUIContent("test"), "box");
GUILayout.EndVertical();
}
the error goes away...
in the script reference guide, it is said that the style is an optional argument
why do i have to explictly provide the style argument for it to work?
i'm using Unity 3.1.0f3 (54715) if that can help
Thanks a lot
NB: i'm building a unity GUI generation framework so it's not just me not wanting to provide the "style" argument. The thing is: the framework isn't supposed to generate this argument when the user didn't supply a style attribute for a BeginVertical element
According to the script reference, it's not optional:
http://unity3d.com/support/documentation/ScriptReference/GUILayout.BeginVertical.html
static function BeginVertical (params options : GUILayoutOption[]) : void
static function BeginVertical (style : GUIStyle, params options : GUILayoutOption[]) : void
static function BeginVertical (text : string, style : GUIStyle, params options : GUILayoutOption[]) : void
static function BeginVertical (image : Texture, style : GUIStyle, params options : GUILayoutOption[]) : void
static function BeginVertical (content : GUIContent, style : GUIStyle, params options : GUILayoutOption[]) : void
The one in question being the last one, which takes a GUIContent, a style, and a variable number of GUILayoutOptions
but have a look at the style argument description:
style The style to use for background image and padding values. +++If left out, the background is transparent.+++
so it actually appears to be optional! look at the "text/style/options" construct for example. If i just provide a text argument and no style, it works!
Thanks a lot for your help Mike, but it didn't really answer my question. As explained in my previous comment, the script reference guide says about the 'style' argument:
The style to use for background image and padding values. If left out, the background is transparent
and when i use the text/style/options constructor, like this:
function OnGUI() {
GUILayout.BeginVertical("test");
GUILayout.EndVertical();
}
it works! i don't have to provide the style argument for it to work!
why is there such a discrepancy between the two constructors?
Oh I see your problem. Just use GUILayout.BeginVertical(); The one you're using right now is trying to parse Test as a GUIStyle (The second function I listed)
Thanks again $$anonymous$$ike, but what about the scripting guide? It clearly says about the style argument: "If left out, the background is transparent". Is it just some random statement that has no value?
or does "left out" means that i must provide an empty string for the style argument? (ins$$anonymous$$d of no style argument at all)
The one I used above is the only function you can leave it out of, the rest are mandatory. It has value in that you're calling BeginVertical without a style, the fact that it's internally a different overload doesn't change that
Ok, i think i understand better now! But what if i want to create a BeginVertical with a text and use the default transparent background for the style. Will BeginVertical("test", "") do the trick?
