How to create a gui button inside an if statement?

Question

Hi I want to know if its possible to create a gui button outside of the OnGUI() function. Is it possible for the code below to work in another if statement? Outside of the OnGUI() function?

 if (GUI.Button(Rect(10,70,100,40),"Drop Ball")) 
         {
             attachedRigidbody = rigidbodyTrigger.rigidbody;
             attachedRigidbody.useGravity = true;
             //guiTrigger = true;
         }

Answer 1

Best Answer

Answer by clunk47 · Oct 30, 2013 at 06:48 PM

NO. You can, however create the String for your label and Rect outside of GUI. If you only want to show your button under a certain condition, use a boolean.

 var showButton : boolean = false;
 var rect : Rect = new Rect(0, 0, 128, 128);
 var label : String = "Click Me";
  
 function Update()
 {
     if(Input.GetKeyDown(KeyCode.S))
     showButton = !showButton;
 }
  
 function OnGUI()
 {
     if(showButton)
     {
         if(GUI.Button(rect, label))
         {
             //YourCodeHere
         }
     }
 }

You can also create GUIContent outside of gui code...

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How to create a gui button inside an if statement?

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