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Question by infinitypbr · Feb 13, 2015 at 07:50 PM · imageserverwwwphpupload

How to grab POST image data from WWWForm on server?

Hello!

My code should be working. I use Prime31 to get a photo from the iOS device photo library, which is then supposed to be uploaded using WWWForm to my server for processing. The code below is working, I am able to use print_r($_POST); on the server to see the text field (Email) that I've submitted. However there's no entry in the array for any data.

How does a guy capture the data on the server? Thanks for any tips!

 function UploadPhoto(fileName : String){
     var screenShotURL        = URL_OF_SERVER_PHP_PAGE;
     var bytes                = System.Text.Encoding.UTF8.GetBytes(fileName);
     var form = new WWWForm();
     form.AddField("userEmail", PlayerPrefs.GetString("Last Email"));
         form.AddBinaryData("fileUpload", bytes, "newPhoto.jpg", "image/jpg");
         // Upload to a cgi script
         var w = WWW(screenShotURL, form);
         yield w;
         if (!String.IsNullOrEmpty(w.error))
             print(w.error);
         else
             print ("Results: " + w.text);
 }


More info, the code below on my server should tell me about any files, I'd think. However it results in:

Results: Upload: Type: Size: 0 Kb Temp file:

 echo "Upload: " . $_FILES["file"]["name"] . "
     "; echo "Type: " . $_FILES["file"]["type"] . "
     "; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb
     "; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "
     ";

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Answer by infinitypbr · Feb 13, 2015 at 08:17 PM

All the above works, except the first field in AddBinaryData should just be "file".

Now on to the next problem.

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