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Question by BZS · Feb 09, 2014 at 09:29 PM · javascriptvariablefunctionfunction update

How to access variable from another function?

Is it possible to access a variable from another function in the same script? I need to access a variable from my update function because if I declare it outside it won't work. Is this possible?

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avatar image uanmanarmy · Feb 09, 2014 at 10:02 PM 0
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Yes, it is possible , as far as i know with get component (script name) , search on google about it.

avatar image Cecilfinal · Feb 09, 2014 at 10:28 PM 0
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$$anonymous$$ay you put an example? Because in my $$anonymous$$d you can access a variable only by saying the name of the variable if its in the same script. From another function? Like a variable in a collision and from the update function?

avatar image Ashish Dwivedi · Feb 10, 2014 at 10:40 AM 0
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It is not possible. Can you tell me why that is not working ?If you want to share variable among methods then you declare it outside and that will work absolutely. But if it is not working means you are doing something wrong. Can you post your code so that I can see why it is not working?

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Answer by DajBuzi · Feb 09, 2014 at 10:42 PM

In my opinion it's impossible to access method variable outside this method. Correct me if i'm wrong but i see something like this:

 function someFunction()
 {
   //You want this variable to be edited in otherFunction();
   var x = value;
 }
 // and here you want to access variable x 
 function otherFunction()
 {
   x = otherValue;
 }

If thats what you want then i think its not possible and you should do loke this:

 //That's your variable that you can access within any method
 var x : int = value;

 function someFunction()
 {
    x = otherValue;
 }

 function otherFunction()
 {
   x = anotherValue;
 }
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avatar image whydoidoit · Feb 10, 2014 at 01:11 PM 1
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Quite right: Apart from some wacky ways of accessing method variables using closures (which would require the other function to be defined inside the first function anyway) then there is no way.

The reason for this is that local variables are defined on the stack as the program executes. When the first function returns the space used by 'x' will rapidly be used by something else. This is why you must assign local variables before using them, they could contain any old stuff otherwise.

When for$$anonymous$$g a closure the compiler magically creates a hidden class and makes what appears to be a local variable a member of that class - therefore it's not on the stack, therefore it works.

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Answer by J-R-Wood · Feb 09, 2014 at 10:30 PM

Yes I think it would look like this as shown on script reference

     `// Calls the function ApplyDamage with a value of 5
 SendMessage ("ApplyDamage", 5.0);
 
 // Every script attached to the game object 
 // that has a ApplyDamage function will be called.
 function ApplyDamage (damage : float) {
     print (damage);
 }`
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