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Question by Daniel G · Jun 27, 2013 at 01:27 PM · javascriptif statementinteger

Integer in if statement, scripting help

Hello, I am new to integers, and I have searched all over the web and i cant find how to properly read an int in an if statement. I want to read the current gear and read the RPM and if its over the threshold and the gear is 0 or 1 ect it subtracts from the realRPM so that the rpm gauge shows a lower RPM on entry to the next gear.

Here is the code:

 public var currentGear : int = 0;
 public var rawRPM:float;
 public var realRPM:float;
 
 function Update {
 
 realRPM=(1000+(rawRPM*17.5));// - ((currentGear)*(3000));
     
     if (realRPM > 7000 && currentGear += 0) {
         realRPM - 3500; //This will set 1 gear start at 4500RPMs
     }
     
     if (realRPM > 6800 && currentGear = 1) {
         realRPM - 3200; //This will set 2 gear start at 4500RPMs
     }
     
     if (realRPM > 6500 && currentGear = 2) {
         realRPM - 3000; //This will set 3 gear start at 4500RPMs
     }
     
     if (realRPM > 6500 && currentGear = 3) {
         realRPM - 3000; //This will set 4 gear start at 4500RPMs
     }
     
     if (realRPM > 6500 && currentGear = 4) {
         realRPM - 3000; //This will set 5 gear start at 4500RPMs
     }
     
     if (realRPM > 6500 && currentGear = 5) {
         realRPM - 3000; //This will set 6 gear start at 4500RPMs
     }
 }
 }
 
 //This is just a snippet from my carMotor script.


Thank you so much!

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avatar image Daniel G · Jun 27, 2013 at 01:29 PM 0
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I was playing with the first if statement, not trying to do anything different from the rest of the if statements!

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Answer by PAEvenson · Jun 27, 2013 at 01:32 PM

in your if statements you are setting currentgear = to a value rather than checking against it ( == ). This might fix your issues:

  if (realRPM > 7000 && currentGear == 0) {
        realRPM - 3500; //This will set 1 gear start at 4500RPMs
     }
  
     if (realRPM > 6800 && currentGear == 1) {
        realRPM - 3200; //This will set 2 gear start at 4500RPMs
     }
  
     if (realRPM > 6500 && currentGear == 2) {
        realRPM - 3000; //This will set 3 gear start at 4500RPMs
     }
  
     if (realRPM > 6500 && currentGear == 3) {
        realRPM - 3000; //This will set 4 gear start at 4500RPMs
     }
  
     if (realRPM > 6500 && currentGear == 4) {
        realRPM - 3000; //This will set 5 gear start at 4500RPMs
     }
  
     if (realRPM > 6500 && currentGear == 5) {
        realRPM - 3000; //This will set 6 gear start at 4500RPMs
     }
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avatar image Daniel G · Jun 27, 2013 at 02:03 PM 0
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Thank you SO much, But i have one more error? its the subtraction of the realRP$$anonymous$$ ex (realRP$$anonymous$$ - 3000;) this is giving me an error too?

avatar image Daniel G · Jun 27, 2013 at 02:09 PM 0
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AH! Yes fixed it :D You need to put (realRP$$anonymous$$ -= 3000;)

for subtract: x -= y for addition: x += y for just equals: ==

Chears thank you PAEvenson!

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