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Question by qwertyk31 · Sep 30, 2013 at 12:24 AM · guifunction

Display GUI when function is called

How can you get a GUI to appear when a function is called. none of the examples in the scripting referance show how to do this. This is what I have so far.

 var windowRect : Rect = Rect (20, 20, 120, 50);
 
 
 
 function OnTriggerEnter (player) 
     {
         Debug.Log("NPC contact");
         NPC_GUI();
     }
 
 function Start () 
 {
     player = GameObject.Find("player");
 }
 
 
 function NPC_GUI()
 {
     // Create GUI
     GUI.Box (Rect (10,10,200,90), "Test");
     
 }
 
 
     

The game runs fine but when NPC_GUI is called I get the error.

ArgumentException: You can only call GUI functions from inside OnGUI. UnityEngine.GUIUtility.CheckOnGUI () UnityEngine.GUI.Box (Rect position, UnityEngine.GUIContent content, UnityEngine.GUIStyle style) UnityEngine.GUI.Box (Rect position, System.String text) dialog.NPC_GUI () (at Assets/Standard Assets/Scripts/my scripts/dialog.js:20) dialog.OnTriggerEnter (System.Object player) (at Assets/Standard Assets/Scripts/my scripts/dialog.js:8)

I think a workaround would be to add a script to a object when the gui is needed then take it away. is there a better way?

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Answer by robertbu · Sep 30, 2013 at 01:54 AM

I think you want something like this:

 var windowRect : Rect = Rect (20, 20, 120, 50);
 private var showGUI = false;
  
 function OnTriggerEnter (player) 
 {
     Debug.Log("NPC contact");
     showGUI = true;
 }
  
 function Start () 
 {
     player = GameObject.Find("player");
 }
  
 function OnGUI()
 {
     // Create GUI
     if (showGUI)
         GUI.Box (Rect (10,10,200,90), "Test");
 }
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Answer by getyour411 · Sep 30, 2013 at 01:51 AM

In OnGUI

 If (somestate is_true)
  GUI.Box (Rect (10,10,200,90), "Test");

some other code sets somestate to false to turn off the GUI component.

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