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Question by artman_12 · Feb 26, 2013 at 09:08 AM · editor-scriptingmenu

How to open file in MonoDevelop by script?

Hello, I am making a custom script template. I want this template to be in menu Assets/Create/CustomTemplate. I created corresponding menu item, and I want to open my previously saved text file (Editor\Data\Resources\ScriptTemplates\CustomTemplate.cs) in default script editor. My question is - is there any way that i can get default script editor via script and give it a path of a file to open?

I am aware that this can be done via System.Diagnostics.Process.Start(), but this will open hardcoded application, not the default script editor. I've searched alot, and the only things I've found is

 UnityEditorInternal.InternalEditorUtility.OpenFileAtLineExternal();


and

 AssetDatabase.OpenAsset();

I think the first one pretty close, but I don't know how I get correct name of the script

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Answer by artman_12 · Feb 26, 2013 at 02:29 PM

I've found out myself, It's possible to use

 UnityEditorInternal.InternalEditorUtility.OpenFileAtLineExternal(@"C:\1.txt", 1);

It wasn't obvious for me that OpenFileAtLineExternal() takes a path, as "filename"

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avatar image Bohofx · Apr 24, 2013 at 02:36 PM 0
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Thanks, this proved to be vastly easier than trying to launch $$anonymous$$onoDevelop as a process correctly on multiple different platforms!

avatar image jj_unity328 · Jul 24, 2018 at 02:20 PM 0
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I haven't been able to open a file not situated in Assets.

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