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Question by OwenBayi · Dec 23, 2012 at 10:35 AM · guimenuifgetkeydown

How to make a GUI appear and disappear with the same button?

Currently I have the script:

 function Start(){
     Menu.enabled = false;
 }
 function Update(){
     if( Input.GetKeyDown( KeyCode.Escape ) ) {
     Menu.enabled = true;
     }
     if( Input.GetKeyUp( KeyCode.Escape ) ) {
     Menu.enabled = false;
     }
 }




Which, as expected, makes the image as long as the key is being pressed. I was wondering how I could put

 If( The Menu is up) {
 Turn it off

And visa versa

thanks in advance

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Answer by Fattie · Dec 23, 2012 at 10:52 AM

Here's the answer !

 if ( Input.GetKeyDown( KeyCode.Escape ) )
    Menu.enabled = ( ! Menu.enabled );

The pling "!" operator, makes a boolean value "swap" to the other value. If it is true, it becomes false. If it is false, it becomes true.

Here's another way to program it that makes sense:

 if ( Input.GetKeyDown( KeyCode.Escape ) ) swapVisibility();

then write a routine swapVisibility(), like this:

 function swapVisibility()
 {
 if ( Menu.enabled )
    {
    Menu.enabled = false;
    return;
    // if you forget the return, it won't work !
    }
 // if you get to here, the menu is not enabled !
 Menu.enabled = true;
 }



Merry Christmas !

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avatar image OwenBayi · Dec 23, 2012 at 06:34 PM 0
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Thanks so much for the help.

Happy Holidays!

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