C# - Another GUI.button in a GUI.button.

Question

So I here's what I want to do. alt text

I click a button to show 'Main Menu'.(It worked.)
Then there will be 3 buttons in Main Menu(It worked.)
I click 'config 1' then show the player another menu.(IT DIDN'T WORK !)

I've benn working on this for an hour but still can't figure it out,need help here,thanks.

So here's my code.

 using UnityEngine;
 using System.Collections;
 
 public class ButtonOption : MonoBehaviour    {
 
     public MainIsactive = false;
     
     void OnMouseUpAsButton() 
     {
         if ( MainIsactive == false )
         {
             MainIsactive = true;
         }
     }
     
     void OnGUI() 
     {
         if ( MainIsactive == true )
         {
             {
                 GUI.Box (new Rect(500,280,400,400),"Title");
             
                 if(GUI.Button(new Rect(865,290,23,23), "X"))
                 {
                     MainIsactive = false;
                 }
             
                 if(GUI.Button(new Rect(650,410,100,50),"Config 1"))
                 {
                     GUI.Box (new Rect(500,280,400,400),"Title2");
                     GUI.Label ( new Rect(615,315,200,200),"Texttt");
                 }
             
                 if(GUI.Button(new Rect(650,500,100,50),"Config 2"))
                 {
                     //Do Something. 
                 }
             
                 if(GUI.Button(new Rect(650,590,100,50),"Config 3"))
                 {
                     //Do Something. 
                 }
                 
             }
                 
         }
     }
 }

I attached this script to option button.

Answer 1

The problem that you're having is similar to why you have a variable(which i don't know how you're not getting a build error when you declare MainIsactive given it doesn't have a type(bool) specified). When you click on "Config 1", for a frame or two you may get the box and label from your if statement, might appear for a blink of an eye, but then it's depending on a mouse click on "Config 1" to make it appear. Look at your code, you're stating, IF Config 1 button is pressed, show what's in this IF statement. Thats fine and dandy for a millisecond or two, but then the button is no longer pressed. You need to either have a little state system, say using a switch case statement and a string, the string will contain the current menu you're on, in the switch statement, use the case that corresponds with that menu and detail the GUI controls you want to appear. OnGUI can be called multiple times per frame.

 using UnityEngine;
 using System.Collections;
  
 public class ButtonOption : MonoBehaviour   {
  
     public MainIsactive = false;
     private string currentMenu = string.Empty;
     
     void OnMouseUpAsButton() 
     {
         if ( MainIsactive == false )
         {
             MainIsactive = true;
         }
     }
  
     void OnGUI() 
     {
         if ( MainIsactive == true )
         {
             GUI.Box (new Rect(500,280,400,400),"Title");
     
             if(GUI.Button(new Rect(865,290,23,23), "X"))
             {
                 MainIsactive = false;
             }
             
             switch (currentMenu)
             {
                 case "config1":
                 {
                     GUI.Box (new Rect(500,280,400,400),"Title2");
                     GUI.Label ( new Rect(615,315,200,200),"Texttt");
                 }
                 break;
                 case "config2":
                 {
                 }
                 break;
                 case "config3":
                 {
                 }
                 break;
                 default:
                 {
                     if(GUI.Button(new Rect(650,410,100,50),"Config 1"))
                     {
                         currentMenu = "config1";
                     }
             
                     if(GUI.Button(new Rect(650,500,100,50),"Config 2"))
                     {
                         currentMenu = "config2";
                     }
             
                     if(GUI.Button(new Rect(650,590,100,50),"Config 3"))
                     {
                         currentMenu = "config3";
                     }
                 }                
             }
         }
     }
 }

for extra points, use an enum structure for your menu's.

Answer 2

Hello,

You display your GUI elements only when the button is clicked

try this :

 using UnityEngine;
 using System.Collections;
  
 public class ButtonOption : MonoBehaviour   {
  
     public MainIsactive = false;
     bool showConfig1 = false;
  
     void OnMouseUpAsButton() 
     {
         if ( MainIsactive == false )
         {
             MainIsactive = true;
         }
     }
  
     void OnGUI() 
     {
         if ( MainIsactive == true )
         {


                 GUI.Box (new Rect(500,280,400,400),"Title");
  
                 if(GUI.Button(new Rect(865,290,23,23), "X"))
                 {
                     MainIsactive = false;
                     showConfig1 = false;
                 }
  
                 if(GUI.Button(new Rect(650,410,100,50),"Config 1"))
                 {
                     showConfig1 = true;
                 }
  
                 if(GUI.Button(new Rect(650,500,100,50),"Config 2"))
                 {
                     showConfig1 = false;
                     //Do Something. 
                 }
  
                 if(GUI.Button(new Rect(650,590,100,50),"Config 3"))
                 {
                     showConfig1 = false;
                     //Do Something. 
                 }
  
                 if(showConfig1)
                 {
                        GUI.Box (new Rect(500,280,400,400),"Title2");
                        GUI.Label ( new Rect(615,315,200,200),"Texttt");
                 }
  
         }
     }
 }

you can use this method to display your other configs, I think there are many other possibilities for that too.

cheers

C# - Another GUI.button in a GUI.button.

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