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Question by chakuze · Apr 26, 2014 at 11:41 AM · javascriptfunction

Function is called twice and I've no idea why

The function attack() is called twice even though it shouldn't be possible, because the counter variable, which I've implented for debug purpose is higher than 0. see this pic for detailed info: http://imgur.com/dECW4yN

thanks in advance for a reply!

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Answer by Desination-X · Apr 26, 2014 at 11:55 AM

Try putting counter++; before AttackDamage(); This should help.

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