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Question by
RichCoggin · Jul 22, 2013 at 01:05 PM ·
guibuttonselectiongrid
Selectiongrid too many action calls...
Hey there,
I have a number of buttons built from a selection grid. What I want to do is when you click a button, it makes just one call/action. At present, it keeps calling and generating multiple instantiations of the object as the button is active I think. Is there a way so it just calls once? Here's my code so far...
using UnityEngine;
using System.Collections;
public class SelectionGridTest : MonoBehaviour
{
public GUISkin leftnav;
public int selGridInt = 0;
public string[] selStrings = new string[] {"Grid 1", "Grid 2", "Grid 3", "Grid 4", "Grid 5", "Grid 6", "Grid 7", "Grid 8"};
//Instansiate object references
public GameObject TheObject;
void OnGUI()
{
GUI.skin = leftnav;
GUI.Box(new Rect(-90,14,100,320),"");
selGridInt = GUI.SelectionGrid(new Rect(40, 40, 70, 800), selGridInt, selStrings, 1);
if (selGridInt == 0)
{
// execute code for loading Object1
GameObject objTheObject = (GameObject)Instantiate(TheObject, new Vector3(0,0,0), transform.rotation);
}
else if (selGridInt == 1)
{
// execute code for loading level //////Application.LoadLevel(1);
}
else if (selGridInt == 2)
{
// execute code for destroying tag
Destroy (GameObject.FindWithTag("TheObject"));
}
}
}
Comment
Answer by aldonaletto · Jul 22, 2013 at 01:45 PM
The variable selGridInt holds the last value selected - that's why the actions repeat continuously. A simple solution is to detect changes with an auxiliary variable - like this:
...
public GameObject TheObject;
private int lastSel = -1; // declare this variable outside any function!
void OnGUI(){
GUI.skin = leftnav;
GUI.Box(new Rect(-90,14,100,320),"");
selGridInt = GUI.SelectionGrid(new Rect(40, 40, 70, 800), selGridInt, selStrings, 1);
if (selGridInt != lastSel){ // selGridInt changed?
lastSel = selGridInt; // yes: update lastSel and take appropriate action
if (selGridInt == 0)
{
// option 0 code
} else
if (selGridInt == 1)
{
// option 1 code
} else
if (selGridInt == 2)
{
// option 2 code
}
}
}
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