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Question by DynamicPrgm · Nov 12, 2012 at 01:27 AM · randomtimerangeinvokerepeating

InvokeRepeating with a variable?

I was wondering if you could possibly use a variable to make InvokeRepeating repeat a random time? for example:

 var randomNumber : float =Random.Range(3, 10);
 
 function Start()
 {
 InvokeRepeating("Test", 1, randomNumber);
 }
 
 function Test()
 {
 print("Success!");
 }

Or perhaps I should do this:

 function Update()
 {
 
 yield WaitForSeconds(random);
 
 var randomNumber : float = Random.Range(3, 10);
 
 }
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Answer by DynamicPrgm · Jan 03, 2013 at 10:21 AM

I figured out what I was trying to accomplish: random generation of a number once every X seconds, for decision making. Heres the code:

     var rand;
     
     function Start()
     {
     InvokeRepeating("RandomRanger", 0, 1.5);
     //sets function to repeat once every 1.5 seconds starting immediately
     }
     
     function RandomRanger()
     {
     var it = Random.Range(1, 5);
     rand = it;
     //makes random number
     }
     
     function Update(){
     print (rand);
     }
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avatar image DynamicPrgm · Mar 14, 2013 at 09:13 PM 0
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Now I realize what I was trying to accomplish was actually not what the question was...I was trying to do this for AI decisions. Now I'm much better at program$$anonymous$$g and am frowning upon my code in the question... I even spelled Yield wrong.

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Answer by Eric5h5 · Nov 12, 2012 at 01:34 AM

If the goal is to have InvokeRepeating use a different length of time whenever it repeats, then no, that's not possible using InvokeRepeating. Instead you can use a coroutine. (But not like your second example, which can't work since Update can never be a coroutine. Just leave Update out of it and use a coroutine.)

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