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Question by VigorousApathy · Jan 16, 2013 at 01:14 PM · randomloopwhiledo

SOLVED! - Pick Number != These Other Numbers

So I'm putting together a script that will pick a number that does not equal other numbers that are based on an instance. I've put together a scrip that does what I think it should do, however it returns a number it should not.

Code Summary: There is a range of numbers from 0 to 4. I'd like it to shuffle through these numbers and pick one that does not equal another set of numbers. However, it still picks the incorrect number.

 do{var pick = Random.Range(0,5;}
                 
 while(pick != Number0 && pick != Number1 && pick != Number2 && pick != Number3 && pick != Number4);

alt text

The correct answer in this case, would be 0 or 1, but it picks 3.

unity01.jpg (34.6 kB)
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avatar image VigorousApathy · Jan 16, 2013 at 01:16 PM 0
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Sorry, do should read like this:

do{var pick = Random.Range(0,5);}

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Answer by VigorousApathy · Jan 16, 2013 at 05:22 PM

SOLVED IT!

Here is the code that does what I intended:

             while(picked == false)
             {
                 var pick = Random.Range(0,5);
                 
                 if(pick != number0 && pick != number1 && pick != number2 && pick != number3 && pick != number4)
                 {
                     yield pick;
                     picked = true;
                 }
             }
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Answer by fafase · Jan 16, 2013 at 01:21 PM

I think your while condition should be the other way around. As long as what is inside is true the condition repeats. I guess you want the invert effect.

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