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Question by Yamilla · Aug 06, 2013 at 11:35 AM · lerpbouncemathfmathf.lerp

Making an object bounce, using Mathf.Lerp

Hi there,

I'm trying to make an object (fireball) bounce between -4 and 10 on the Y Axis, without Rigidbody, and such. Instead, the object gets stuck on the exact same position.

 void Update () {
     if (transform.position.y == -4) {
         transform.position = new Vector3(transform.position.x,Mathf.Lerp(min,max,Time.time),transform.position.z);
     }
     if (transform.position.y == 10) {
         transform.position = new Vector3(transform.position.x,Mathf.Lerp(max,min,Time.time),transform.position.z);
     }
 }

I suspect the "==" causes the trouble, but ">" and "<" cause other problems.

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avatar image Benproductions1 · Aug 06, 2013 at 11:37 AM 0
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Just as a side note, you don't have to go:

 transform.position = new Vector3(transform.position.x, value, transform.position.z);

You can simply go:

 transform.position.y = value;

It's much easer, much nicer and also faster :)

avatar image Deequation · Jan 04, 2014 at 05:48 AM 1
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& on a side note, to the side note, totally wrong and misleading post. If you look at the syntax you will see it is written in C#, not JS. In C# you can't edit directly into vector3 components, but you need to re-create the vector3 and feed it back in, so no. Also as far as faster goes, when the variable type is a vector3, it has to re-create the entire vector3 anyhow, JS just hides this fact from you by doing it automaticly, so faster, that's another no. However, 'nicer', you can have that one.

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Answer by robhuhn · Aug 06, 2013 at 11:46 AM

The position.y hits unlikely exactly -4 or 10. Using Mathf.PingPong could be what you are after:

 void Update () {
     transform.position = new Vector3(transform.position.x, Mathf.PingPong(Time.time * speed, 14) - 4, transform.position.z);
 }

Another approach is using Mathf.Sin (returns -1 to 1) which gives an in/out easing.

 void Update () {
     transform.position = new Vector3(transform.position.x, Mathf.Sin(Time.time * speed) * 7 + 3, transform.position.z);
 }


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