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Question by ImPhilip · Jul 29, 2014 at 04:18 PM · ifchat

Pressing a button to make chat appear and disappear

 public bool useChat = true;
 
 if(useChat){
                     if(Input.GetKeyDown(KeyCode.Return)){
                         if(viewChat) {
                             viewChat=true;
                             print("true");
                         } else {
                             viewChat=false;
                             print("false");
                         }                
                     }

Im trying to make it so when I press enter it shows the chat and if I press enter again the chat disappears. Right now when I press enter. Nothing shows up but in the console it says both true and false

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avatar image dsada · Jul 29, 2014 at 04:28 PM 1
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FYI You can do this in C#: viewChat = !viewChat that is an easy and cant be written wrong if you just want to switch a bool value :)

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Answer by Lazdude17 · Jul 29, 2014 at 04:26 PM

You are only setting viewChat to true if viewChat is true... Is there some other code that also affects the viewChat variable?

I think what you want is

 if(Input.GetKeyDown(KeyCode.Return)) //If you hit enter
 {
    if(viewChat) //And if viewChat is true, meaning chat is open
    {
         viewChat = false; //Then close the chat
    }
    else
    {
        viewChat = true; //Otherwise turn chat on if the opposite is true
    }
    print(viewChat); //Show me what viewChat is every time I press enter
 }


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avatar image ImPhilip · Jul 29, 2014 at 05:08 PM 0
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It still doesn't show. But when I change Get$$anonymous$$eyDown to Get$$anonymous$$ey When I hold enter, the chatbox shows

avatar image Lazdude17 · Jul 29, 2014 at 05:42 PM 0
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Are you running this under the Update() function? You should always check for input in the Update() function.

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Answer by feyyd · Jul 29, 2014 at 04:39 PM

Snippet will toggle viewChat when Return is pressed, print true or false.

 if( Input.GetKeyDown(KeyCode.Return) )
 {
     viewChat = !viewChat;
     if ( viewChat ) Debug.Log ("true");
     else Debug.Log ("false");
 }
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