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Question by jessee03 · May 19, 2011 at 06:30 AM · guitexturefindactive

hide and show gui texture problem

Here is my script.

function Update () {

if (Input.GetKeyDown(KeyCode.N)){

GameObject.Find("playerbag").guiTexture.active = true; }

if (Input.GetKeyDown(KeyCode.M)) {

GameObject.Find("playerbag").guiTexture.active = false; }

}

The problem I'm having is I am able to press M to hide my gui but when I go to press N it will not show itself. Anyone know what I might be doing wrong ?

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avatar image jessee03 · May 19, 2011 at 03:48 PM 0
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Also when I have my code for clicking an object and hiding the same gui it doesn't work at all. Even though pressing a key makes it work.

avatar image Jessy · May 23, 2011 at 04:39 PM 0
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Why did you use .active? Why did you not read what the Console said? It tells you how to fix your problem.

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Answer by HHameline · May 23, 2011 at 05:15 PM

I would consider doing something like this instead:

 private bool showGui = true;
 void OnGUI()
 {
     if(Input.GetKeyDown("m"))
     {
          showGui = false;
     }
     if(Input.GetKeyDown("n"))
     {
          showGui = true;
     }
     GUI.enabled = showGui;
     <INSERT GUI CODE HERE>
     GUI.enabled = true;
 }


Your GUI Code should probably just be something like:

 GUI.DrawTexture([Position Rectangle], [Image Texture]);

My code is in C# but it shouldn't be to difficult to translate into Javascript.

If you have never used Unities OnGUI function I have left a link below. Keep in mind that the OnGUI function runs twice per frame. It is incredibly handy.

Heres that link.

Hope that helps. Hans

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Answer by Jessy · May 23, 2011 at 04:39 PM

Your code doesn't do what you think it does. You're deactivating the entire entire Game Object, and GameObject.Find doesn't find inactive objects.

http://unity3d.com/support/documentation/ScriptReference/Behaviour-enabled.html?from=GUITexture

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