koobas.hobune.stream
Access one child of object with many duplicate names
Hello,
I'm following a tutorial where we create a cube called "brick" in the hierarchy, then we duplicate it a couple of time, we create an empty object called "row", drag all the "brick" objects under the "row", duplicate the rows a couple of time, create an empty object called wall and put all the rows under it.
So, my Hierarchy looks something like this :
Wall
Row
Brick
BrickRow
Brick
Brick
Now, I make a script and I would like to access my objects from the script. I can use GameObject.Find("Wall") to find my wall and it works fine. I know I could use GameObject.Find("Wall/Row"); but what when I have multiple item called Row? Is there a way to get something like GameObject.Find("Wall/Row[0]")?
I thought I could use the foreach but when I write this line :
foreach( GameObject rangee in mur )
I get the following error : error CS1579: foreach statement cannot operate on variables of type UnityEngine.GameObject' because it does not contain a definition for GetEnumerator' or is not accessible
What am I doing wrong with the foreach? Plus is there a way to use the GameObject.Find on objects that have the same name?
You need to use Transform instead of GameObject in your foreach, because Transform is IEnumerable and GameObject isn't.
Ok, thank you, it's working well if I use the foreach with an IEnumerable component ins$$anonymous$$d of the GameObject. New question that comes to my $$anonymous$$d and I'm asking it even if I haven't searched for it yet, can you get the GameObject that contains the component we get? (I'll search for this right away)
Still, in the first place, is there a way to get something like GameObject.Find("Wall/Row[0]") since all my bricks share the same name? Can I use the FindObject on objects with the same name?
Accessing the parent of the transform is easy: Transform.parent.
For finding objects with the same name, you're best to use Tags. Have a look at this example and the for loop they set up: GameObject.FindGameObjectsWithTag.
