Question by Fepalito · Dec 30, 2017 at 02:39 AM · c#scripting problem trigger collision detection booleans

How to Trigger/collision only once time per gameobject hit's?

Soo first sorry for the English and second I'm making a AoE(Area of Effect) skill dmg in my game with collider/trigger but I have a problem when the Collider/trigger skill hit he can dmg multiple time the same enemy. but i want to only dmg once and once time each one!(if multiples enemy get hit) l tryed make a Bool array but don't work and i'm out of way what to do, becaus if I use only one boolean he will only triggers once the dmg and never triggers again. Like a explosion that grow and has 3s duration if a enemy is inside he will trigger every time the collider push the gameObject and I don't know a way to check what enemy are damaged.

Here is the code I tryed:

 Bool[] alreadyHits;
 ...
 private void OnTriggerEnter(Collider colisao)
     {
         y = enemies.Length; // from a enemys list
         for(int x=0;x<=y;x++)
         {
             if (colisao.gameObject == enemies[x])
             {
                 if (colisao.GetComponent<enemy01>() != null && !alreadyHits[x]) //becaus I have multiples script of enemys
                 {
                     print("get hit");
                     enemy01 ene01 = colisao.GetComponent<enemy01>();
                     ene01.getHit(dmg);
                     alreadyHits[x] = true;
                 }
             }
         }
         
     }

but don't work at all. here is a example what I need:

 A check list if already hit X enemy:
 Enemy1 = alreadyHit? if no > do dmg, if yes > don't do dmg 
 Enemy2 = alreadyHit? if no > do dmg, if yes > don't do dmg 
 EnemyX = alreadyHit? if no > do dmg, if yes > don't do dmg etc
 and is only in this instanciete skill if recast it i want to to one dmg again etc.

Now I have to figurate what to do I already try searching in multiples sites and in the forums but only find the one time trigger and is not I want anyone can help me?(and sorry if already exist here in the forum this thread)

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