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Question by strikeric11 · Sep 13, 2016 at 03:05 AM · c#unity 5

loop until u find non duplicate

I have this code:

 chknext = Random.Range(0, 6);
 
 int checkmonspawn()
     {
         getrannum = Random.Range(0, 4);
 
         if (getrannum == chcknext)
         {
             getrannum = Random.Range(0, 4);
         }
         return getrannum;
 

if getrannum and chcknext is the same, getrannum will get another random number. Problem is sometimes he gets the same number What is the efficient way to do this?

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avatar image DavidWatts · Sep 13, 2016 at 03:10 AM 1
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You could change if to while. It's a quick and dirty solution but not a good one if it needs to be called a lot.

avatar image juicyz · Sep 13, 2016 at 04:17 PM 0
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Is there any certain reason why you are calling Random.range two-three times? What are you trying to achieve with using two random integers? Also assu$$anonymous$$g you declared chknext and getrannum as ints?

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Answer by AurimasBlazulionis · Sep 13, 2016 at 03:58 AM

You can easily change if (getrannum == chcknext) to while (getrannum == chcknext). This will repeat the steps until not the same number will get generated. This is completely safe, because I can not even imagine 10 times in a row to get 2 generated. And we are talking about this being run on modern computers, which can do millions of computations a second.

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