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Question by XenosTiger · Dec 03, 2018 at 12:00 AM · unity 2dunity5coroutinesfunctions

How to get a constantly updating variable to a non-constantly updated function.

I have a script that is used for player combat, in which pressing different buttons calls on different functions and coroutines that instantiate projectiles from the players position. However, I am struggling to find a way to constantly update the player's position inside these functions/coroutines since they're only being run once. Here's an example:

 void Update () {
         Vector2 player = new Vector2(transform.position.x, transform.position.y);
 
  if (Input.GetKeyDown(KeyCode.R)) {
             StartCoroutine(RapidShoot(1, player));
         }
 }
 
 
  IEnumerator RapidShoot (float rapidShootTime, Vector2 player) {
 
         while (rapidShootTime > 0) {
             rapidShootTime -= Time.deltaTime;
             GameObject newBullet = Instantiate(bullet, player, Quaternion.identity);
             newBullet.transform.SetParent(gameObject.transform, true);
             yield return new WaitForSeconds(.05f);
         }
     }


I would appreciate any help possible, thanks!

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Answer by Vega4Life · Dec 03, 2018 at 12:15 AM

You don't need to reference the position in Update() as you already have it through transform.position. Just do this:


     void Update()
     {
         if (Input.GetKeyDown(KeyCode.R))
         {
             StartCoroutine(RapidShoot(1));
         }
     }
 
 
     IEnumerator RapidShoot(float rapidShootTime)
     {
 
         while (rapidShootTime > 0)
         {
             rapidShootTime -= Time.deltaTime;
 
             Vector2 playerPosition = new Vector2(transform.position.x, transform.position.y);
             GameObject newBullet = Instantiate(bullet, playerPosition, Quaternion.identity);
             newBullet.transform.SetParent(gameObject.transform, true);
             yield return new WaitForSeconds(.05f);
         }
     }



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avatar image XenosTiger · Dec 03, 2018 at 12:24 AM 0
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Ah. $$anonymous$$istakes like these re$$anonymous$$d me that I'm still a beginner with lots to learn. Thanks so much.

avatar image Vega4Life XenosTiger · Dec 03, 2018 at 12:42 AM 0
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No problem, good luck!

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