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Question by Jibidiah · Sep 13, 2011 at 03:20 AM · null reference

Random Null Reference Exception

This part of the script works, I'm just getting a null reference exception being thrown out even though it works.

         if (EggNumber == 30f) {
         SpawnerScript otharScript = GameObject.Find("SpawnObject").GetComponent<SpawnerScript>();
         otharScript.Die();
     }

It causes no problems, I guess I want to get this solved in case if it somehow does later.

Part of the error message:

 NullReferenceException
 
 UnityEngine.GameObject.GetComponent[SpawnerScript] ()
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avatar image GuyTidhar · Sep 13, 2011 at 08:25 AM 0
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Where is this code snippet residing?

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Answer by Sirithang · Sep 13, 2011 at 01:17 PM

Looking at the error, it seems that GameObject.Find("SpawnObject") return null, because it cannot find the GameObject your looking for.

You should try :

  if (EggNumber == 30f) 
  {
    GameObject lFoundObj = GameObject.Find("SpawnObject");
    if(lFoundObj != null)
    {
         SpawnerScript otharScript =   lFoundObj.GetComponent<SpawnerScript>();
         if(otharScript != null) // better to check if the script was retrieved too
         {
             otharScript.Die();
         }
     }
  }
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Answer by msknapp · Sep 13, 2011 at 01:18 PM

Either your game object returns null, meaning it does not exist in the scene, or the game object does not have the script attached to it. Try this:

if (EggNumber == 30f) {
GameObject g = (GameObject)GameObject.Find("SpawnObject");
if (g != null) {
SpawnerScript otharScript = g.GetComponent<SpawnerScript>();
if (otharScript != null) {
otharScript.Die();
} else {
Debug.LogWarning("otharScript was null.");
}
} else {
Debug.LogWarning("Game object was null.");
}
}

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