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Question by Stealthygolem · Oct 21, 2014 at 11:50 PM · c#gameobjectinstantiaterandom

C# 2d Instantiate object randomly around gameobject

Hello! I think that there probably is a simple solution to this, but, browsing google and different threads around here, I just get more confused, rather than enlightened.

So this is what my Random instantiate code looks like:

     void Start () {
         InvokeRepeating("Spawn", SpawnStartDelay, SpawnRate);
     }
 
     void Spawn() {
         Vector2 position = new Vector2(Random.Range(-10.0F, 10.0F),Random.Range(-10.0F, 10.0F));
         Instantiate(enemyPrefab, position, Quaternion.identity);

So, how do I reference a "this.gameobject.transform.position" in this kind of script? I've been trying different things without success. They just spawn randomly on axis 0,0, as expected.

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Answer by SarperS · Oct 22, 2014 at 12:39 AM

 const float range = 10.0f;
 
 private void Spawn() {
     var randomPos = Random.insideUnitSphere * range;
     randomPos.y = 0;
     Instantiate(enemyPrefab, transform.position + randomPos, Quaternion.identity);
 }
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avatar image Stealthygolem · Oct 22, 2014 at 03:00 PM 1
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Thank you! This did work. But, in my topdown 2d game I would have to use randomPos.z = wanted value.

And for someone using C#, this is what the code ended up looking like:

     private void Spawn() {
         Vector3 randomPos = Random.insideUnitSphere * range;
         randomPos.z = -1;
 
         Instantiate(enemyPrefab, transform.position + randomPos, Quaternion.identity);
 
avatar image AMU4u · May 01, 2015 at 03:17 AM 0
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Thanks, sarper!

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