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Question by SonicDirewolf · Oct 23, 2017 at 01:24 PM · instantiateobjectrandomenemyspawn

Spawning different random objects at the same position?

I've been trying to spawn two objects at random. But the random function generates only one random value at runtime, and so only one of the object gets spawned. I want both of them to spawn at random intervals. Help!

Thank You!

      public float SpawnTime;
      public GameObject Object1;
      public GameObject Object2;
      private int i;
  
      // Use this for initialization
      void Start () {
          i = Random.Range (1, 6);
  
          StartSpawn ();
      }
      
      
      void Update () {
          
  }
  
      public void StartSpawn() {
          if (i > 3) {
              
              InvokeRepeating ("SpawnObject1", 0.2f, SpawnTime);
          }
          else 
              InvokeRepeating ("SpawnObject2", 0.2f, SpawnTime);
  
      }
  
  
      void SpawnObject1(){
      
          Instantiate(Object1, new Vector3(transform.position.x,0,0), Quaternion.identity);
      }
  
      void SpawnObject2(){
  
          Instantiate(Object2, new Vector3(transform.position.x,0,0), Quaternion.identity);
      }
  
  }
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Answer by NoseKills · Oct 23, 2017 at 01:50 PM

If the only thing you want to randomise is the object you instantiate, there's really no reason to have multiple different method calls. And if you want to spawn a different object every time, you should call Random.Range() every time you Instantiate, not just once when the app/level starts.

 void SpawnRandomObject(){
           int i = Random.Range(1, 6);
           GameObject obj;
           if (i > 3){
                obj = Object1;
           } else {
                obj = Object2;
           }
           Instantiate(obj, new Vector3(transform.position.x,0,0), Quaternion.identity);
       }


Then just "InvokeRepeating" this one method.

Note that Random.Range with integers never returns the second parameter, so with (1, 6) it returns numbers 1, 2, 3, 4 and 5, making object 1 spawn less often than 2

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avatar image SonicDirewolf · Oct 23, 2017 at 02:03 PM 1
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Thank you so much! Worked perfectly. And yeah, I know that the max range in Random.Range for float is inclusive and for int, it's exclusive. Thanks for the tip!

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Answer by Dragate · Oct 23, 2017 at 01:43 PM

Start() is executed once, that's why you get only one random value.

   public float SpawnTime;
   public GameObject Object1;
   public GameObject Object2;
  
   // Use this for initialization
   void Start () {
       StartCoroutine(SpawnObject ());
   }
   
   public IEnumerator SpawnObject() {
       int i = Random.Range (1, 6);
       if (i > 3){
           Instantiate(Object1, new Vector3(transform.position.x,0,0), Quaternion.identity);
       }else{
           Instantiate(Object2, new Vector3(transform.position.x,0,0), Quaternion.identity);
       }
       yield return new WaitForSeconds(SpawnTime);
       StartCoroutine(SpawnObject ());
   }
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