Debug log to website.

PHP Stuff

Check out the php function file_put_contents to write data to a file.

Example Usage:

 <?php
 
 $data = $_POST["debugdata"];
 
 if(isset($data))
 {
    $file = 'debuglog.txt';
    
    // Write the contents to the file
    file_put_contents($file, $data);
 }
 
 ?>

Unity Stuff

You'll want to look into sending post requests to a url using the www class and create a function with which you can easily add new debug statements. Check here for a way to extend Debug.Log.

Example (Add this to a gameobject in your scene):

 using UnityEngine;
 using System.Text;
 using System.Collections;
 
 public class DebugData : MonoBehaviour
 {
     public static DebugData Instance;
 
     private StringBuilder sb = new StringBuilder();
 
 
     void Awake ()
     {
         Instance = this;
     }
     
     public void AddDebug (string log)
     {
         sb.Append(log);
         sb.Append("\n");
     }
 
     public void PostDebugData ()
     {
         StartCoroutine(Post(sb.ToString()));
     }
 
     public IEnumerator Post (string data)
     {
         string url = "http://yoururl.com/yourdebugfile.php";
 
         // Create a Web Form
         var form = new WWWForm();
         form.AddField("debugdata", data);
 
         WWW w = new WWW(url, form);
         yield return w;
 
         if (!string.IsNullOrEmpty(w.error))
             print(w.error);
         else
             print("Finished sending debug data.");
     }
 }

Then you can add debug logs using DebugData.Instance.AddDebug("Hello World!"); and post the data using DebugData.Instance.PostDebugData();

Create a table on your website called "Log" with 2 columns "ID" Primary Key and "LogString" as varchar.

Your application will use WWW class and WWWForms.

 string Debug_URL = "http://www.url_to_use_with_http";
     IEnumerator logData(string logStringToSendToWebServer)
     {
         WWWForm form = new WWWForm();
         form.AddField("logString",logStringToSendToWebServer);
         WWW get = new WWW(Debug_URL,form);
         yield return get;
         if (get.text == "done")
         {
             //finish code
         }
         else
         { 
             //fail recovery code
         }
     }

You php code should be something like this.

 #Connect to the database
 #check validation of some sort
 
 #Take data
 $logValueToEnterIntoDatabase = $_POST["logString"];
 
 #insert data into database by changing the value to be added as $logValueToEnterIntoDatabase