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Question by Wyko · Jun 25, 2011 at 12:08 AM · switchlocalswitch-case

Variable usage in Switch Statements

Why does the following code throw: There is already a local variable with the name 'wall'? They are all in different parts of the switch, so shouldn't the variable be unique?

 switch (type){
 case 0 :
     var tile : Transform = Instantiate(tilePrefab.transform, new Vector3(x,0,z),Quaternion.identity);
     tile.name = TileArray[x, z].Name();
     
     break;
 
 case 1 : 
     var wall : Transform = Instantiate(wallPrefab.transform, new Vector3(x,0.6,z),Quaternion.identity);
     wall.name = TileArray[x, z].Name();
     break;
     
 case 2 : 
     var wall : Transform = Instantiate(wallPrefab.transform, new Vector3(x,0.6,z),Quaternion.identity);
     wall.name = TileArray[x, z].Name();
     break;

 }
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avatar image _Petroz · Jun 25, 2011 at 12:35 AM 1
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You can create scope using { }

 case 1:
 {
     // some code here
     break;
 }
avatar image Eric5h5 · Jun 25, 2011 at 01:30 AM 1
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You'd probably be better off using arrays anyway:

 var tilePrefabs : Transform[];
 ...
 var tile : Transform = Instantiate (tilePrefab[type], new Vector3(x,0,z),Quaternion.identity);
 tile.name = TileArray[x, z].Name();

Then you don't need switch/case at all.

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Answer by ckfinite · Jun 25, 2011 at 12:17 AM

No. The parts of a switch statement are not like the body of a if statement or a loop, i.e. they don't have their own scope. Anyway, it isn't really good variable naming practice to reuse the same name.

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Answer by Grim_Darknight · Apr 30, 2013 at 11:46 PM

The reason it tells you you already have one is because of the double declaration. Define your variable outside the switch statement once then use it.

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