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Question by DarkSlash · Aug 31, 2013 at 03:05 PM · updatefunctiononguiinvokecalling

Call a function once from OnGUI

I got a function that I want to call just once from OnGUI. There're some IF, and if some condition is match, I need to call the Exit() function, that shows a GUI.Label, waits 2 secconds, and then exits. The thing is that the function is not called once, but each time OnGUI is executed. How can I solve this?

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avatar image ahaykal · Aug 31, 2013 at 03:16 PM 1
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what I would do is add a boolean with the IF that you're talking about. When the if is executed make ur boolean false. if(someboolean && somecoditionmatched) someboolean = false;

avatar image DryTear · Aug 31, 2013 at 04:29 PM 0
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so you basically want a pop up message that stays on screen for 2 seconds, right?

and to run GUI once, just set that bool true, and then instantly to false.

avatar image DarkSlash · Aug 31, 2013 at 07:31 PM 0
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I did the boolean solution but I was thinking that may be there're was an ad hoc solution! Something like InvokeOnce!

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Answer by Srimasis · Aug 31, 2013 at 07:04 PM

Declare a variable runonce=0;

 inside OnGUI()
 
 if(functionShouldBeCalled==1 && runonce==0) {
 runYourFunc();
 runonce=1;
 }
 if( functionNeedsToBeCalledAgain==1) {
 functionShouldBeCalled=1;
 runonce=0;            //this will run your desired function once in next frame
 }
 
 }
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Answer by astracat111 · Apr 17, 2017 at 01:18 PM

You can use a state machine.

 private enum State { Start, Update }
 private State state;
 
 void OnGUI() { 
         switch (state) {
         case State.Start:
             Debug.Log ("run once");
 
             state = State.Update;
             break;
 
         case State.Update: 
             Debug.Log ("run every frame");
 
             break;
         }
     }
 
     void OnFocus() { 
         state = State.Start;
     }


I'm going to try to use this to load and save xml file data. I would assume that one doesn't want to load an xml file (or any data file for that matter) every frame.

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